{"id":17332,"date":"2018-03-25T23:21:26","date_gmt":"2018-03-25T23:21:26","guid":{"rendered":"http:\/\/sitepourvtc.com\/?page_id=17332"},"modified":"2022-11-11T05:11:43","modified_gmt":"2022-11-11T05:11:43","slug":"guy-lussacs-law","status":"publish","type":"page","link":"https:\/\/sitepourvtc.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/gas-laws\/guy-lussacs-law\/","title":{"rendered":"Guy-Lussac\u2019s Law"},"content":{"rendered":"
Guy-Lussac\u2019s\u00a0law<\/strong> or the pressure law<\/strong> is one of the gas laws, and it states that:<\/p>\n

For a fixed mass of gas at constant volume, the pressure is directly proportional to the Kelvin temperature.<\/em><\/p>\n<\/div><\/div>\n

Guy-Lussac\u2019s Law<\/strong> or the Pressure Law<\/strong> is one of the gas laws. In the late 18th and early 19th centuries, it was discovered by French chemist Joseph Louis Gay-Lussac<\/strong>. He studied the relationship between the pressure<\/strong> and the temperature<\/strong> of a gas at constant volume<\/strong>. The results of certain experiments with gases at relatively low pressure led Joseph Louis Gay-Lussac to formulate a well-known \u201cPressure Law<\/strong>\u201d. It states that:<\/p>\n

For a fixed mass of gas at constant volume, the pressure is directly proportional to the Kelvin temperature.<\/em><\/p>\n

That means that, for example, if you double the temperature, you will double the pressure. If you halve the temperature, you will halve the pressure.<\/p>\n

You can express this mathematically as:<\/p>\n

p = constant . T<\/em><\/span><\/strong><\/p>\n

Yes, it seems to be identical to the isochoric process of an ideal gas. These results are fully consistent with the ideal gas law, which determinates that the constant is equal to nR\/V. If you rearrange the pV = nRT equation by dividing both sides by V, you will obtain:<\/p>\n

p = nR\/V \u00a0. \u00a0T<\/em><\/span><\/strong><\/p>\n

where nR\/V is constant and:<\/p>\n